Question 1037701
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If each brick accounts for 6 inches of the circumference of the garden and there are 50 bricks, then the circumference of the garden is 50 times 6 in inches.  However, since the coverage of a bag of dirt is given in square feet, it will be more convenient to note that 6 inches is one-half of a foot, and then the circumference, in feet, will be 50 times 1/2 feet.


Once you know the circumference, then you can calculate the radius using:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ r\ =\ \frac{C}{2\pi}]


And then you can calculate the area of the garden


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ A\ =\ \pi r^2\ =\ \pi\left(\frac{C}{2\pi}\right)^2]


Which simplifies to:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ A\ =\ \frac{C^2}{4\pi}]


Once you know the area, presuming you used feet as the circumference measurement unit, just divide by 10 and round UP to the nearest whole number.  You round up because most garden supply places won't sell you fractional parts of a bag of dirt.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  

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