Question 1037624
for 3 and 2 

x=3  

x-3=0 eq1 

x=2  

x-2=0 eq2

then multiply the two equation

(x-3)*(x-2)=0  by foil method you will the quadratic eq.

x^2-2x-3x+6= 0

={{{x^2-5x+6=0}}}



for 1 and 3

x=1  
x-1=0
x=3 
x-3=0

(x-1)*(x-3)=0

x^2-3x-1x+3=0

={{{x^2-4x+3=0}}}