Question 1037536
Unclear description.


(x^2+14x-18/2x^2+x-6)=1

Also not fully clear.  



Put in the missing grouping symbols.
(x^2+14x-18)/(2x^2+x-6)=1
{{{(x^2+14x-18)/(2x^2+x-6)=1}}}


That numerator seems to be not factorable.  Maybe you could still try to solve the equation for the variable.  Your question was about dividing one expression by another.  Try POLYNOMIAL LONG DIVISION.


... Why do you have your rational expression set equal to 1?
{{{x^2+14x-18=2x^2+x-6}}} would be an equivalent equation although potentially without the same restriction.
-
{{{2x^2-x^2+x-14x-6+18=0}}}
{{{x^2-13x+12=0}}}
{{{(x-1)(x-12)=0}}}
-
SOLUTION,  {{{system(x=1, or, x=12)}}}



Do either of these fail in the original equation?  Look at the denominator.
-
{{{2x^2+x-6}}}
{{{2(1)^2+1-6}}}
{{{2+1-6}}}
{{{-3}}}
-
{{{2*12^2+12-6}}}
{{{288+6}}}
-
Neither of those are 0, so both solutions will work.