Question 1037503
{{{drawing(400,400,-.9,4.9,-.9,4.9,

graph(400,400,-.9,4.9,-.9,4.9), line(0,4,4,0), arc(0,0,2,-2,0,90) )}}}  

The area of the triangle is 

{{{A=expr(1/2)*base*height - expr(1/2)*4*4 = 8}}}

The area of the quarter circle, which is 1/4 of the 
area of the unit circle = {{{expr(1/4)*pi*r^2=expr(1/4)*pi*1^2=expr(1/4)pi}}}

Subtracting the quarter circle's area from the triangle's
area:

{{{8-pi/4}}}

Edwin</pre>