Question 1037489
The formula is:
{{{ A = A[0]*( 1/2 )^(t/h) }}}
{{{ A = 75*( 1/2 )^( 1/5.2 ) }}}
{{{ A = 75*( 1/2 )^.19231 }}}
{{{ A = 75*.8752 }}}
{{{ A = 65.64 }}}
65.64 grams will be left after 1 year
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check:
{{{ A = 75*( 1/2 )^.19231 }}}
{{{ 65.64 = 75*( 1/2 )^.19231 }}}
{{{ .8752 = ( .5 )^.19231 }}}
{{{ .8752 = .8752 }}}
OK