Question 89804
{{{x^2+x-2=0  }}}

********Solution #1:  solve with {{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
for equation like {{{ax^2 + bx + c = 0 }}}
In this case, a=1, b=1, c=-2

*******Solution #2: Solve by factoring
{{{x^2+x-2=0  }}}
{{{(x+2)(x-1)=0  }}}
x = -2, 1