Question 89798
y=x^2+x-6  [factor]
0=(x-2)(x+3) [set the equation equal to zero]
.
0=x-2 [set each factor equal to zero and solve for the x-term]
2=x
or 
0=(x+3)
-3=x
.
So, x  = 2 or x=-3  [the intercepts]
.
Check by plugging the values of (x) back into the orginal equation and solve.