Question 1037280
a triangle has three angles 110, 50 and 20. the longest side is 5 cm longer than the smallest side. Determine the perimeter of the triangle
------------
The smallest side is opposite the smallest angle.
x = length of smallest side
---
x/sin(20) = (x+5)/sin(110)
x*sin(110) = (x+5)*sin(20) = x*sin(20) + 5sin(20)
x*(sin(110) - sin(20)) = 5sin(20)
x = 5sin(20)/(sin(110) - sin(20))
x =~ 2.861267
Longest side = 7.861267
----
Find the 3rd side.  Call it s:
x/sin(20) = s/sin(50)
s = x*sin(50)/sin(20)
s =~ 6.40856
================
Add those to find the perimeter.