Question 1037200
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solve 8^3x-3=4^3x-4
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<pre>
{{{8^(3x-3)}}} = {{{4^(3x-4)}}}.

Write both sides with the base "2" using 8 = {{{2^3}}}  and  4 = {{{2^2}}}. You will get

{{{2^(3*(3x-3))}}} = {{{2^(2*(3x-4))}}}.

Since the base are equal, the indexes are equal too:

3*(3x-3) = 2*(3x-4).

Simplify and solve it for x.
</pre>

By the way, here is how to write correctly your equation when posting to this site:


8^(3x-3) = 4^(3x-4).


Use it when you will be posting next time.