Question 1037140

(2x-1)^2 = 9
Solve for x.

Do I expand the brackets?
<pre>{{{(2x - 1)^2 = 9}}}
No, that'd be too much work!
{{{(2x - 1)^2 = 3^2}}}
2x - 1 = 3 ------- EXPONENTS are equal, and so are the BASES 
2x = 3 + 1
2x = 4
{{{highlight_green(matrix(1,3, x = 4/2, or, x = 2))}}}