Question 1037110
<pre><b>
Instead of doing yours for you, I'll do
one exactly like yours step by step. 
You can then do your equation exactly
the same way:

{{{27(3^(2x+4)) = 3sqrt(3^x)}}}

Divide both sides by 3

{{{9(3^(2x+4)) = sqrt(3^x)}}}

Square both sides:

{{{81(3^(2x+4))^2 = 3^x}}}

Multiply the exponents on the left,
the outer 2 by the inner exponent 2x+4:

{{{81(3^(4x+8)) = 3^x}}}

Write 81 as 3<sup>4</sup>

{{{3^4(3^(4x+8)) = 3^x}}}

Add the exponents of 3 on the left:

{{{3^(4+(4x+8))=3^x}}}

Since the bases are same positive numbers
on both sides and they are not equal to 1,
we may set the exponents equal to each other
and ignore the bases:

{{{4+(4x+8)=x}}}

{{{4+4x+8=x}}}

{{{12+4x=x}}}

{{{4x=x-12}}}

{{{3x=-12}}}

{{{x=-4}}}

Now use the above as a model and solve yours 
exactly the same way, step by step.

Edwin</pre></b>