Question 1036843
8x+x^2-2y=64-y^2 
put in form of x^2+y^2=r^2, where r is some number.
x^2+8x+y^2-2y=64
complete the square for both terms
x^2+8x+16+y^2-2y+1=64+16+1, because I have to add 16 to both sides.
(x+4)^2+(y-1)^2=81
It will be a circle with radius 9 and center of (-4,1)