Question 1036783
This is a paired t-test
Ho:mean =0
Ha:mean ne0.
alpha=0.05
test stat is t, df=44 critical value abs(t)>2.01
t is mean over SE
calculation: SE is 18.3/sqrt (45)=2.73; mean/SE=1.25
Fail to reject Ho
CI is mean +/- t*SE=3.4 +/-2.01*2.73 and the product is 5.49.
The interval is (-2.09,8.89). The interval contains 0, so 0, or no change, is a plausible value, and there is no convincing evidence that garlic affects LDL cholesterol levels.