Question 1036748
{{{f(x)=x^2-x-6=(x+2)(x-3)}}}
{{{g(x)=(x-3)/(x+2)}}}
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{{{f/g=((x+2)(x-3))/((x-3)/(x+2))}}}
{{{f/g=((x+2)(x-3)(x+2))/(x-3)}}}
{{{f/g=(x+2)^2}}}, with {{{x<>-2}}}