Question 1036655
Start with the inner most function h(x). Plug in x = 2.


h(x) = x^2+1
h(2) = 2^2+1
h(2) = 4+1
h(2) = 5


So (g o h)(2) = g(h(2)) = g(5). Let's find the value of g(5)


g(x) = 4x
g(5) = 4*5 ... plug in x = 5
g(5) = 20



That means

(g o h)(2) = g(h(2))
(g o h)(2) = g(5)
(g o h)(2) = 20


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[f o (g o h)](2) = f[ g(h(2)) ]
[f o (g o h)](2) = f[ g(5) ]
[f o (g o h)](2) = f[ 20 ]


Let's find the value of f(20)


f(x) = 2x - 1
f(20) = 2*20 - 1
f(20) = 40 - 1
f(20) = 39



The final answer is A) 39.