Question 1036653
.10x+(12-x)=.40(12). The amount of 10% antifreeze is .10x, pure antifreeze is 12 gallons- what is x, and the end result is 40% antifreeze.
.10x+12-x=4.8
-.90x=-7.2
x=8 gallons of .10
12-x=4 gallons of pure.
2/3 is 10%, and the resultant is 2/3s of the way from 100% down to 10%.