<PRE><B>Question 1036579</B>
Hi there,
The total cost of 4 apples and 5 oranges is $44.
4x + 5y = 44......(1)
hen 1 apple and 2 oranges are removed from the lot,
the cost is reduced by $14. 
3x + 3y = 30......(2)
................
4x + 5y = 44......(1)
3x + 3y = 30......(2)
Multiply Eq(1) by 3
Multiply Eq(2) by 4
12x + 15y = 132....(1)
12x + 12y = 120....(2)
Subtract Eq(2) from Eq(1)
.....3y = 12
......y = 4
Substitute y = 4 into Eq(1)
4x + 5y = 44......(1)
4x +5(4) = 44
4x + 20 = 44
4x = 44 - 20
4x = 24
x = 6
Apple costs $6
Orange costs $4
Hope this helps :-)</PRE>