Question 1036534

Divide 76 into two parts so that two-thirds of one part is equalto 3/5 of the other part
<pre>Let 1st part be F
Then other part is: 76 - F
We then get: {{{(2/3)F = (3/5)(76 - F)}}}_____{{{2F/3 = 3(76 - F)/5}}}_____{{{2F/3 = (228- 3F)/5}}}
5(2F) = 3(228 - 3F) ------- Cross-multiplying
10F = 684 - 9F
10F + 9F = 684
19F = 684
F, or 1st part = {{{684/19}}}, or{{{highlight_green(36)}}}
Other part: 76 - 36, or {{{highlight_green(40)}}}