Question 1036509
 square root of 128x^3 over the square root of 2xy.
{{{sqrt(128x^3)/sqrt(2xy)}}}
we can factor inside the top radical to reveal perfect squares
{{{sqrt(64*2*x^2*x)/sqrt(2xy)}}}
extract the square roots of those perfect square
{{{8x*sqrt(2x)/sqrt(2xy)}}}
we can write the denominators as
{{{8x*sqrt(2x)/(sqrt(2x)*sqrt(y))}}}
we can cancel {{{sqrt(2x)}}}
{{{(8x)/sqrt(y)}}}