Question 1036483

How to determine the equation of a parabola with vertex (7,-2) and passing the point (6,0)? Graph the parabola.
So far I have gotten 
y=a(x+b)^2+c
y=a(x+6)^2+0
<pre>No, no, no!! The vertex form of a parabola is the equation: {{{y = a(x - h)^2 + k}}}. In this case, (h, k) = (7, 2), and (x, y) = (6, 0). 
You substituted (x, y) for (h, k). That's incorrect! Try again!