Question 1036482
Description discusses lengths and an area.


Dimension for the SQUARE are  2(3x+1)  and 2(3x+1).
Area of the square is  {{{2^2*(3x+1)^2}}}.


Let the length of the rectangle be  L.
Given is that width of the rectangle is  3x+1.
Area of the rectangle is  {{{(3x+1)L}}}.



Also given is that ......
...  {{{(3x+1)L=2^2(3x+1)^2}}}, and the question asked is, what is L.