Question 1036447
a)


{{{g(x)= 3x^2-5x+4}}}



{{{g(0)= 3(0)^2-5(0)+4}}} Replace every copy of 'x' with 0. Now evaluate.



{{{g(0)= 3(0)-5(0)+4}}}



{{{g(0)= 0-0+4}}}



{{{g(0)= 4}}}


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b)


{{{g(x)= 3x^2-5x+4}}}



{{{g(-1)= 3(-1)^2-5(-1)+4}}} Replace every copy of 'x' with -1. Now evaluate.



{{{g(-1)= 3(1)-5(-1)+4}}}



{{{g(-1)= 3+5+4}}}



{{{g(-1)= 12}}}


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c)


{{{g(x)= 3x^2-5x+4}}}



{{{g(3)= 3(3)^2-5(3)+4}}} Replace every copy of 'x' with 3. Now evaluate.



{{{g(3)= 3(9)-5(3)+4}}}



{{{g(3)= 27-15+4}}}



{{{g(3)= 16}}}


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d) 


{{{g(x)= 3x^2-5x+4}}}



{{{g(-x)= 3(-x)^2-5(-x)+4}}} Replace every copy of 'x' with '-x'. Then simplify.



{{{g(-x)= 3x^2+5x+4}}} 



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e) 


{{{g(x)= 3x^2-5x+4}}}



{{{g(1-t)= 3(1-t)^2-5(1-t)+4}}} Replace every copy of 'x' with '1-t'. Then expand and simplify.



{{{g(1-t)= 3(1-2t+t^2)-5(1-t)+4}}}



{{{g(1-t)= 3-6t+3t^2-5+5t+4}}}



{{{g(1-t)= 3t^2-t+2}}}