Question 1036353
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0/any = 0.


{{{-1/sqrt(0)}}} doesn't exist


{{{-4/sort(1-16)}}} = {{{-4/sqrt(-15)}}} doesn't exist.


{{{2/3}}} divided by {{{sqrt(1 -(2/3)^2)}}} is {{{2/3}}} divided by {{{sqrt(5)/3}}}.  


So the final ratio is {{{2/sqrt(5)}}} = {{{(2*sqrt(5))/5}}}.



This is written partly for the student and partly for the previous tutor to help him to learn writing formulas in this site.


To see the original "code", press the button "EDIT THIS SOLUTION" under my posting.