Question 1036282
Hi there,
sin^2x = 2 - 2cosx
Using cos^2x + sin^2x = 1
so, sin^2x = 1 - cos^2x
1 - cos^2x = 2 - 2cosx
Rearrange.
cos^2x - 2cosx + 1 = 0
(cosx - 1)(cosx - 1) = 0
cosx - 1 = 0
cosx = 1
x = 0, 2π
Hope this helps :-)