Question 1036195
log n + log(n+3) = 2
log(n(n+3)) = 2
If we are working with log base 10,
log(n(n+3)) = log(100), since log(100) = 2
So n(n+3) = 100
n^2 + 3n = 100
add -100 to each side
n^2 + 3n - 100 = 0
By quadratic formula
n = {{{ -(3/2) - (sqrt(409))/2 }}}
n = {{{ (sqrt(409))/2 -(3/2)  }}}