Question 1036186
*[tex \large \tan 69^{\circ} = \frac{h}{131+x}] where x is the distance from the 80-degree angle endpoint to the midpoint of the base of the arch.


*[tex \large \tan 80^{\circ} = \frac{h}{x}]


Then *[tex \large x = \frac{h}{\tan 80^{\circ}]. Substitute expression for x into the first equation to obtain:


*[tex \large \tan 69^{\circ} = \frac{h}{131 +\frac{h}{\tan 80^{\circ}}]


Solve for h, and use your calculator to evaluate *[tex \large \tan 69^{\circ}] and *[tex \large 80^{\circ}].