<PRE><B>Question 1036057</B>
The front of an A-frame cabin in a national park is in the shape of a triangle, with an area of 189 ft^2. If the height is 1 ft less than twice the base, find the base and the height of the front of the cabin?
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A = (1/2)*base*height
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189 = (1/2)*b*(2b-1)
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378 = 2b^2 - 2b
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2b^2 - 2b - 378 = 0
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b^2 - b - 189 = 0
Use the Quadratic formula to get::
base = 14.26 ft
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height = 2b-1 = 28.52-1 = 27.52 ft
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Cheers,
Stan H.</PRE>