Question 1036064
Given that
{{{1/x=a+b}}} and {{{1/y=a-b}}}
we are able to switch x with a+b and y with a-b...it takes two steps but it is perfectly proper...this gives us
{{{x = 1/(a+b)}}} and {{{y = 1/(a-b)}}}
so that
x + y = {{{1/(a+b) + 1/(a-b)}}}
Now to combine these, there is a shortcut, but let us just change both fractions to their common denominator (a+b)(a-b)...like this
={{{(a-b)/((a+b)(a-b)) + (a+b)/((a+b)(a-b))}}}=
{{{2a/((a+b)(a-b))}}}