Question 1036014
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Given that sinx = 3/5 and cosy = 7/25, with x and y both being Quadrant I angles, find cosx AND siny
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cos(x) = {{{sqrt(1-sin^2(x))}}} = {{{sqrt(1 - (3/5)^2)}}} = {{{sqrt(1 - 9/25)}}} = {{{sqrt((25-9)/25)}}} = {{{sqrt(16/25)}}} = {{{4/5}}}.


The sign  "+"  was chosen at the square root because the cosine is positive in the first quadrant.


Similarly,  sin(y) = {{{sqrt(1-cos^2(y))}}} = {{{sqrt(1-(7/25)^2)}}} = {{{sqrt((625-49)/625)}}} = {{{sqrt(576/625)}}} = {{{24/25}}}.

The sign  "+"  was chosen at the square root because the sine is positive in the first quadrant.
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