Question 1036005
A company that manufacturers paint cans designed a can that has a radius or 3 inches and a volume of 83 cubic inches. For a new can design the company plans to keep the height the same and double the radius. What will be the affect on the can's volume? 
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Original can DATA
Volume = pi*r^2*h
83 = pi*3^2*h

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New design DATA
V = pi*(2*3)^2*h
Rearrange::
V = pi*3^2*2^2*h
V = pi(3^2)h *2^2
V = 83*4
Ans:: The volume will be multiplied by 4.
Cheers,
Stan H.
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