Question 1035980
 How many gallons of a 70​% antifreeze solution must be mixed with 90 gallons of 25​% antifreeze to get a mixture that is 60​% ​antifreeze? Use the​ six-step method. can you help me do this type proble? 
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Equation::
anti + anti = anti
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0.70x + 0.25*90 = 0.60(x + 90)
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70x + 25*90 = 60x + 60*90
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10x = 35*90
x = 9*35
x = 315 gallons (amt. of 70% solution needed)
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Cheers,
Stan H.
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