Question 1035902
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The length of the {{{highlight(cross(triangle))}}} rectangle is 1 cm more than the width. If the perimeter of the rectangle is 6 cm, then what are the dimensions of the rectangle.
The width of a rectangle is 2/3 of its length. Find its length if the perimeter is 80 cm. Find its dimensions.
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1. The length of the rectangle is 1 cm more than the width. 
    If the perimeter of the rectangle is 6 cm, then what are the dimensions of the rectangle.


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Let L be the rectangle length ans W be the rectangle width. Then

L - W = 1,     (1)   ( "The length of the rectangle is 1 cm more than the width" )
L + W = 3.     (2)   ( 3 is half of 6, half of the perimeter. Do you understand why this equation (2) is true?  It is the key! )

Now, to solve the system (1), (2), add the equations (1) and (2). You will get

2L = 1 + 3 = 4,   hence,   L = {{{4/2}}} = 2.  So, you just found the length L.

Next, find W from equation (2): W = 3 - L = 3 - 2 = 1.

The problem is solved.

<U>Answer</U>. L = 2, W = 1.
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