Question 1035842
{{{9/x-x/(x^2-8)}}} becomes zero at x = 3 and x  = -3, as can be easily solved.  

9/x is undefined at x = 0.  {{{x^2-8}}} is zero at {{{x = -2sqrt(2)}}} and {{{x = 2sqrt(2)}}}.

Therefore the expression is continuous only at x = -1.  In the other choices it is discontinuous.