<PRE><B>Question 1035774</B>
d^2s/dt^2=4e^4t
ds/dt=e^4t+C1; t=0, ds/dt=5, or C1=4, since e^0=1;
v=ds/dt=e^4t+4
therefore, 
s=(1/4)e^4t+4t+C; if t=0, s=2; 2=(1/4)+C, and C=7/4
s=(1/4e^(4t)+4t+7/4
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when t=5, position is (1/4)e^20+20+(7/4), and the distance is 121,291,318.6, subtracting the 2 at the end for the initial position.
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