Question 1035733
For a right regular hexagonal pyramid, the volume is found by
{{{V = (1/3)Bh}}}
Here the base is a regular hexagon whose area is given by
{{{B = (3sqrt(3)/2)*s^2 = (3sqrt(3)/2)*64 = 96sqrt(3)}}}
Thus the volume is
{{{V = (1/3)*96sqrt(3)*9 = 288sqrt(3) = 498.8}}}cm^3