Question 89454
find all values of y such that the distance between (3,y) and (-2,9) is 12.
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d = sqrt((3--2)^2 + (y-9)^2)
12 = sqrt( 25 + (y-9)^2)
144 = 25 + (y-9)^2
119 = (y-9)^2
y = sqrt119 +9 or y = -sqrt119+9
y=19.909 or y= -1.909
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Cheers,
stan H.