Question 1035639

explain how you fine the vertex and axis summary of the parabola for 
y=-2x^ -12x-16
<pre>{{{y = 2x^2 - 12x - 16}}}
{{{f(x) = 2x^2 - 12x - 16}}}
{{{y = ax^2 + bx + c}}} ----- General form of a quadratic equation
The x-coordinate of the vertex, or the axis of symmetry occurs at {{{x = - b/(2a)}}}
The y-coordinate of the vertex occurs at: {{{f(- b/(2a))}}}
The vertex is located at: {{{highlight_green(matrix(1,4, "(x", ",", f(- b/(2a)), ")"))}}}