Question 1035652
Since Susan leaves the Birchwood station 15 minutes before Meaghan leaves, she travels a distance of 55/60*15 miles, or 13.75 miles. The distance between the two of them is now 50-13.75, or 36.25 miles. Since they are traveling towards each other, we can add velocities, or 55+70=125 mph. 36.25/125=.29 hours, or 17.4 minutes after 7:30 p.m. arrival time, or 7:47 and 24 seconds, p.m.!!!!!!!!!!!