Question 1035561

<pre>
You just substitute k=2 through k=7 in the expression after  
the &#931;, then add them all.

Start by substituting k=2 in
{{{81(-1/3)^(2-2)}}}
{{{81(-1/3)^(0) }}}
{{{81(1) }}}
{{{81}}}

Substitute k=3 in
{{{81(-1/3)^(3-2)}}}
{{{81(-1/3)^1 }}}
{{{81(-1/3) }}}
{{{-27}}}

Substitute k=4 in
{{{81(-1/3)^(4-2)}}}
{{{81(-1/3)^2 }}}
{{{81(1/9) }}}
{{{9}}}

Substitute k=5 in
{{{81(-1/3)^(5-2)}}}
{{{81(-1/3)^3 }}}
{{{81(-1/27) }}}
{{{-3}}}

Substitute k=6 in
{{{81(-1/3)^(6-2)}}}
{{{81(-1/3)^4 }}}
{{{81(1/81) }}}
{{{1}}}

Substitute k=7 in
{{{81(-1/3)^(7-2)}}}
{{{81(-1/3)^5 }}}
{{{81(-1/243) }}}
{{{-81/243}}}
{{{-1/3}}}

Now sum them all up:

{{{81-27+9-3+1-1/3}}}
{{{61-1/3}}}
{{{60&2/3}}}
{{{182/3}}}

Edwin</pre>