Question 89425
the minimum value (or the maximum value if x^2 was negative) lies on the axis of symmetry


the equation for the axis of symmetry is x=-b/2a ... in this case, x=-5/2


to find the value for the minimum, just plug into the equation ... Q(x)=(-5/2)^2+5(-5/2)-36 ... Q(x)=-42.25