Question 1035432

Consider three consecutive odd integers. The sum of the first integer and 2 times the second is 54 more than the third. Find the integers.
<pre>Let smallest/first integer be F
Then others are: F + 2, and F + 4
We then get: F + 2(F + 2) = F + 4 + 54
F + 2F + 4 = F + 58
3F - F = 58 - 4
2F = 54
F, or smallest/first integer = {{{54/2}}}, or {{{highlight_green(27)}}}
Other 2: {{{highlight_green(matrix(1,7, 27 + 2, or, 29, and, 27 + 4, or, 31))}}}