Question 1035431
You must mean to say "degrees" and not "percent".  This would seem to perfectly fit the use of Law of Cosines.  


{{{14^2+14^2-2*14*14*cos(80)=b^2}}} and b is for base size of the triangle.


Next, you want the height.  Your base angles each are 50 degree.  The height segment forms two right triangles, each with a leg {{{b/2}}}.


Area will be  {{{(1/2)(b/2)*h}}}; and you would now already have calculated b.  You might just use Pythagorean Theorem formula,  {{{h^2+((1/2)b)^2=14^2}}}.