Question 1035334
 Find the local max/min point for the function: 
f (x) = x + 16/x 
{{{graph(400,400,-10,10,-10,10,x+(16/x))}}}
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f'(x) = 1 -16/x^2
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Solve 1-16/x^2 = 0
16/x^2 = 1
x^2 = 16
x = +4 or x = -4
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Please note correction::
Local Maximum:::::: (-4,-8)
Local Minimum:::::: (4,8)
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Cheers,
Stan H.
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