Question 1035130
p(A) = 0.80, p(B) = 0.20, p(D|A) = 0.05, p(non-D|A) = 0.95

and p(D|B) = 0.10, p(non-D|B) = 0.90

==> p(A|D) = P(A and D)/p(D) = (p(D|A)*p(A))/p(D) = {{{(0.05*0.80)/(0.05*0.80 + 0.20*0.10) = 2/3}}}