Question 89384
(35Q^9/9Q^5)/(25Q^6/10Q^5) TAKING THESE TERMS SEPARATELY WE HAVE:
35Q^9/9Q^5=35Q^4/9 &
25Q^6/10Q^5=5Q/2 NOW WE INVERT THE SECOND TERM & MULTIPLY.
(35Q^4/9)(2/5Q)=(7Q^3*2)/9=14Q^3/9 ANSWER.