Question 1035219
log(base 5) x + log(base 5) (4x+1)= 1
log(base 5) [x(4x+1)] = 1
x(4x+1) = 5^1
4x^2+x = 5
4x^2+x-5 = 0
factoring:
(4x+5)(x-1) = 0
x = {-5/4, 1}
throw out the neg solution (extraneous) leaving:
x = 1