Question 1035220

(1/3)^-3 = 27^-x I do not know how to solve this. Please show me how. 
<pre>{{{(1/3)^(- 3) = 27^(- x)}}} 
{{{(3^(- 1))^(- 3) = (3^3)^(- x)}}} ------- Changing {{{matrix(1,3, 1/3, to, 3^(- 1))}}}, and {{{matrix(1,3, 27, to, 3^3)}}}
{{{3^3 = 3^(- 3x)}}} 
3 = - 3x ------- Bases are equal, and so are their exponents
{{{3/(- 3) = x}}}______{{{highlight_green(- 1 = x)}}}