Question 1035183
Let n= speed on return trip. Then traveling to speed is n+11. So:
350/n+350/n+11=18
350(n+11)+350n=18(n^2+11n)
350n+350n+3850=18n^2+198n
18n^2-502n-3850=0
Using the quadratic formula, n=34.15. N+11=45.15!!!!!!!!