Question 1035172
{{{x^16-y^8 = (x^8+y^4)(x^8-y^4) = (x^8+y^4)(x^4+y^2)(x^4-y^2) = (x^8+y^4)(x^4+y^2)(x^2 + y)(x^2 - y)}}}

Now we can continue to factor, but that is the best we can do using real numbers...