<PRE><B>Question 1035159</B>
find the value for sin(x/2) if the following conditions hold tan(x)=-4/3 and x is in quadrant IV
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tan = y/x
r = sqrt(y^2 + x^2) = 5
sin(x) = y/r = -4/5
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sin^2(x/2) = (1 - cos(x))/2 *****  Much simpler than the sin(x/2)
cos(x) = x/r = 3/5 --- cosine is + in Q4
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sin^2(x/2) = (2/5)/2 = 1/5
sin(x/2) = sqrt(1/5) = sqrt(5)/5</PRE>